2+3+[n-(2+3)]=n

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Solution for 2+3+[n-(2+3)]=n equation:


Simplifying
2 + 3 + [n + -1(2 + 3)] = n

Combine like terms: 2 + 3 = 5
2 + 3 + [n + -1(5)] = n

Multiply -1 * 5
2 + 3 + [n + -5] = n

Reorder the terms:
2 + 3 + [-5 + n] = n

Remove brackets around [-5 + n]
2 + 3 + -5 + n = n

Combine like terms: 2 + 3 = 5
5 + -5 + n = n

Combine like terms: 5 + -5 = 0
0 + n = n
n = n

Add '-1n' to each side of the equation.
n + -1n = n + -1n

Combine like terms: n + -1n = 0
0 = n + -1n

Combine like terms: n + -1n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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